the angle between the lines 2x=3y=-z and 6x=-y=-4z is|Find the angle between the two lines `2x = 3y = : Pilipinas 1 Answer. votes. answered Mar 19, 2021 by MukeshKumar (30.9k points) selected Mar 19, 2021 by Rupa01. Best answer. Given lines are. 2x = 3y = - z and 6x = - . Access the extensive archive of Powerball results for 2016. Find the winning numbers, prize payouts, and other valuable data from previous Powerball lottery draws. Explore the past results and gain insights into the Powerball game's history.
the angle between the lines 2x=3y=-z and 6x=-y=-4z is,Mathematics. Distinguish Acute Angle Bisectors and Obtuse Angle Bisectors. The angle bet. Question. The angle between the lines 2x= 3y= −z and 6x= −y= −4z is. A. 0∘. B. .
Solution. The equations of the given lines can be re-written as x 3 = y 2 = z − 6 and x 2 = y − 12 = z − 3. We know that angle between the lines x − x 1 a 1 = y − y 1 b 1 = z − z 1 c 1 . The angle between the lines 2x = 3y = – z and 6x = -y = -4z is:A.0°B.90°C.45°D.30°. Ans: Hint: We will simplify the given equation of lines in the .
Solution. 2x = 3y = -z. x 3 = y 2 = Z - 6. and 6x = -y = -4z. cos θ = | a 1 a 2 + b 1 b 2 + c 1 c 2 a 1 2 + b |. = | 3 ( 4) + 2 ( - 24) + ( - 6) - 6 ( 3 2 + 2 2 + 6 2). ( 4 2 + 24 2 + 6 2) |. = | 12 - .
1 Answer. votes. answered Mar 19, 2021 by MukeshKumar (30.9k points) selected Mar 19, 2021 by Rupa01. Best answer. Given lines are. 2x = 3y = - z and 6x = - .
Question. The angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z is. A. 30 o. B. 45 o. C. 90 o. D. 0 o. Solution. Verified by Toppr. Correct option is C. 90 o. Was this .Solution. Verified by Toppr. Was this answer helpful? 0. Similar Questions. Q 1. Find the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. View Solution. Q 2. Angle .Find the angle between the lines 2x=3y=-z and 6x =-y=-4z. If a line makes angles α, β and γ with the axes respectively, then cos 2 α + cos 2 β + cos 2 γ = The equation of a line is .Write the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. The value of m for which the straight lines 3x – 2y + z + 3 = 0 = 4x – 3y + 4z + 1 are parallel to the plane 2x – y + mz = 2 is (a) 6 asked Jan 13, 2020 in Three-dimensional geometry by Nakul01 ( 36.4k points)Angle between the lines 2 x = 3 y = − z, 6 x = − y = − 4 z is 90 Since a 1 a 2 + b 1 b 2 + c 1 c 2 = 0. where a 1 = 1 2 , a 2 = 1 6 , b 1 = 1 3 , b 2 = − 1 , c 1 = − 1 , c 2 = − 1 4Find the angle between the two lines `2x = 3y = The angle between the lines 2x=3y=−z and 6x=−y =−4z is. 11 mins ago. Discuss this question LIVE. Text solution Verified. (d) Given, equation of lines can be rewritten as. 1/2x = 1/3y = −1z. and 1/6x = −1y = −1/4z. ∴ cosθ = a12+b12+c12 a22+b22+c22a1a2+b1b2+c1c2. = 41+91+1 361+1+16121×61+31×(−1)−1×(−41)
Write the angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines 2 x 3 y frac 3.the angle between the lines 2x=3y=-z and 6x=-y=-4z is Find the angle between the two lines `2x = 3y = Find the angle between the lines $$2x = 3y = -z$$ and $$6x = -y = -4z$$. View Solution. Q3. Find the angle between the lines 2 x = 3 y =-z and 6 x =-y =-4 z. [CBSE 2015] View Solution. Q4. Write the angle between the lines $$2x = 3y = -z$$ and $$6x = -y = -4z$$. View Solution. Q5. The angle between the lines $$2x=3y=-z$$ and $$6x=-y=-4z$$ is?Find the angle between the two lines `2x = 3y = -z and 6x =-y = -4z` Find the angle between the lines whose direction cosines are given by the equations: 3l + m + 5n = 0 and 6mn – 2nl + 5lm = 0. Find the angle between the lines whose direction cosines are given by the equations l + m + n = 0, l 2 + m 2 – n 2 = 0.Angle between the lines 2x = 3y =−z and 6x =−y =−4z is. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines 2x3yz and 6xy4z is 2.KEAM 2015: The angle between the lines 2x=3y=-z and 6x=-y=-4z is (A) (π/6) (B) (π/4) (C) (π/3) (D) (π/2) (E) (2π/3). Check Answer and Solution fothe angle between the lines 2x=3y=-z and 6x=-y=-4z isFind the angle between the lines 2x=3y=-z and 6x =-y=-4z. If a line makes angles α, β and γ with the axes respectively, then cos 2 α + cos 2 β + cos 2 γ =. The equation of a line is 2x -2 = 3y +1 = 6z -2 find the direction ratios and also find the vector equation of the line.
Find the angle between the lines 2x = 3y = -z and 6x = -y = -4z See answers Advertisement Advertisement shadowsabers03 shadowsabers03 Consider the line, . This implies the direction ratios are perpendicular to each other, so are the lines and . Hence the angle between the lines is 90 .
The direction ratios of the line x – y + z – 5 = 0 = x – 3y – 6 are proportional to A. 3, 1, –2 B. 2, –4, 1 asked May 28, 2021 in Straight Lines by Aeny ( 45.1k points) straight line in space
Q. The angle between the lines 2x=3y=−z and 6x=−y=−4z is. Q. The angle between the lines 2x=3y=−zand6x=−y=−4z is. Q. The angle between the line 2x=3y=−z and 6x=−y=−4z is. Q. Find the angle between the lines 2 x = 3 y = - z and 6 x = - y = - . The angle between the lines 2x = 3y = – z and 6x = -y = -4z is: A.0° B.90° C.45° D.30° - Brainly.in. profile. banikoul9052. Writes that since both the lines intersect at the origin, the shortest distance between the two lines is 0 units. Given below are two lines L1 and L2: L1: 2x = 3y = -z L2: 6x = -y = -4z i . two lines. ii) Find the shortest distance between the two lines.
The angle between the line \[2x = 3y = - z\] and \[6x = - y = - 4z\] is A. \[90^\circ \] B. \[0^\circ \] C. \[30^\circ \] D. \[45^\circ \]The angle between the lines 2x = 3y= −zand 6x = −y = −4z is. View Solution. Click here:point_up_2:to get an answer to your question :writing_hand:the angle between the lines2x3yzand6xy4zis.The angle between the lines 2 x = 3 y = − z and 6 x = − y = − 4 z is. View Solution. Q3. Find the angle between the lines 2x=3y =-z and 6x=-y=-4z. View Solution. Q4.
The angle between the lines represented by the equation (x 2 + y 2) s i n θ + 2 x y = 0 is. View Solution. Q5. The straight lines joining the origin to the points of intersection of the line 2x + y = 1 and curve 3 x 2 + 4 x y .
the angle between the lines 2x=3y=-z and 6x=-y=-4z is|Find the angle between the two lines `2x = 3y =
PH0 · Write the angle between the lines 2x = 3y =
PH1 · Write the Angle Between the Lines 2x = 3y = −Z and 6x = −Y
PH2 · The angle between the lines 2x=3y=
PH3 · The angle between the lines 2x = 3y = – z and 6x =
PH4 · The angle between the lines 2x = 3y = z and 6x = y= 4z is
PH5 · Find the angle between the two lines `2x = 3y =
PH6 · Find the angle between the lines 2x = 3y = – z and 6x = – y = – 4z
PH7 · Find the angle between the lines 2x = 3y =
PH8 · Find the Angle Between the Lines 2x=3y=